Important Profit and Loss Problem Shortcut Tricks Bank PO SSC Railway Exam Type-3

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Last updated on March 7th, 2021 at 11:41 am

Profit and Loss Problem with solution and Shortcut Tricks for Bank PO SSC Railway Exam Type-3

In Profit And Loss Type-3 , Type-3.1, Type-3.2, Type-3.3 and Type-3.4 .I am going to discuss some important Profit And Loss Problem with solution and Shortcut Tricks For Bank PO, SSC CGL, SSC CHSL, Railway Exam.

The common and frequently asked a question of Profit and Loss Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-3.

For Example:

(Q1)A vendor bought bananas at 6 for Rs 10 and sold them at 4 for Rs 6.Find his gain or loss percent.

Solution: By Concept And Shortcut Tricks

Profit And Loss Problem With Solution

Step-2:

Profit and Loss Problem with solution

C.P= 40 and S.P= 36

Loss= C.P – S.P => 40 – 36 = Rs 4

% Loss= (4×100)/40

= 10% Ans.

CONCEPT:[इस Type के Problem को solve करते Time Object को Only Equal बनाना है| एवं Object को equal बनाने के लिए जिस Number से Multiply किया जायेगा उसी Number से Rate वाले part को Multiply करना है]

Note: Above वाले method से आप लोग इस तरह के problem को 10 sec में solve कर सकते है और Formula याद रखने के कोई जरूरत नहीं है|

(Q2)A man buys lemons at the rate of 3 for Rs 5 and sells them at 2 for Rs 4 what is the profit percent?

Solution: By Concept And Shortcut Tricks

Profit and Loss Problem with solution

C.P=Rs 10 and S.P=Rs 12

Profit= S.P – C.P

=Rs(12-10) = Rs 2

% profit= (2×100)/10

= 20% Ans.

(Q3)A man purchases some oranges at a rate of 3 for Rs 40 and same quantity at 5 for Rs 60. If he sells all the oranges at the rate of 3 for Rs 50, find his gain or loss percentage.

Solution: By Concept And Shortcut Tricks

Profit and Loss Problem with solution

Now,

Profit and Loss Problem with solution

C.P=Rs 380 And S.P=Rs 500

Profit= S.P – C.P

= Rs(500 – 380)

= Rs 120

% profit= (120×100)/380

= 32% Ans.

The common and frequently asked a question of Profit and Loss Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-3.1

(Q1)The cost price of 15 articles is same as the selling price of 10 articles. The profit percent is.

Solution: By Concept And Shortcut Tricks

C.P of 15 articles = S.P of 10 articles

C.P/S.P = 10/15

Profit= S.P – C.P

=> 15-10 => 5 articles

∴ Profit %= (5×100)/10

= 50% Ans.

By Tricks:

Profit And Loss Problem With Solution

= ((15-10)/10)×100

= (5/10)×100

= 50% Ans.

(Q2)The selling price of 12 objects is equal to the cost price of 9 objects. Find the Loss or Profit percentage?

Solution: By Concept And Shortcut Tricks

S.P of 12 objects = C.P of 9 objects

S.P/C.P = 9/12

Note:C.P>S.P so loss

Loss= C.P – S.P

= 12 – 9 = 3

%Loss= (3×100)/12

= 25% Ans.

By Tricks:

Profit And Loss Problem With Solution

= ((12-9)/12)×100

= (3/12)×100

= 25% Ans.

(Q3)By selling 33m cloth a shopkeeper earns profit equivalent to selling price of 11m. Find his profit percent.

Solution: By Concept And Shortcut Tricks

Profit     =    S.P – C.P

S.P(11m) = s.p(33m) – C.P(33m)

⇒ C.P(33m) = s.p(33m) – S.P(11m)

⇒ C.P(33m) = s.p(22m)

⇒C.P/S.P = 22m/33m

Profit= 33m – 22m = 11m

% Profit= (11×100)/22

= 50% Ans

By Tricks:

% Profit= (Profit/S.P-Profit)×100

= (11/33-11)×100

= (11/22)×100

= 50% Ans.

(Q4)By selling 33m, a shopkeeper incurs loss equivalent to the cost price of 11m. Find his loss percent.

Solution: By Concept And Shortcut Tricks

Loss     = C.P – S.P

C.P(11m) = C.P(33m) – S.P(33m)

⇒ S.P(33m) = C.P(33m) – C.P(11m)

⇒ S.P(33m) = C.P(22m)

⇒ S.P/C.P = 22m/33m

Loss= (33-22)m = 11m

%Loss= (11×100)/33

= 33 ¹/3% Ans.

The common and frequently asked a question of Profit and Loss Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-3.2

If two article are sold at equal prices, the First one is sold at X% profit whereas the second one at a loss of X% then the seller always incurs a loss in the entire Transition.

It is equal to ( X)²/100

(Q1) A dealer sold two T.V sets for Rs 7400 each on one he gained 10% and on the other, he lost 10%. The dealer’s loss or gain in the transaction is.

Solution:

% Loss = ( X)²/100

= (10)²/100

= 100/100 = 1% Ans.

(Q2) a dealer sold two T.V sets for Rs 990 each on one he gained 10% and on the other he lost 10%. Then

(1)Find total C.P of T.V.

(2)His loss on the whole in Rs is.

Solution:

% Loss= ( X)²/100

= (10)²/100

= 100/100 = 1%

Profit And Loss Problem With Solution

x × (100-1)/100 = 1980

x × 99/100 = 1980

∴ x = (1980×100)/99

= Rs 2000 Ans.

(2)Loss= C.P – S.P

= Rs(2000 – 1980)

= Rs 20 Ans.

The common and frequently asked a question of Profit and Loss Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-3.3

Trick: If two article is bought at equal prices, the First one is sold at X% profit whereas the second one at a loss of X% then the seller always incurs a no loss and no profit in the entire Transition.

(Q1)A dealer bought two T.V sets for Rs 7400 each. The First one is sold at 10% profit whereas the second one at a loss of 10%. Then find out loss or gain in the transaction.

Solution: No Loss And No Profit.

Note:[We know that If two article is bought at an equal price, the First one is sold at X% profit whereas the second one at a loss of X% then the seller always incurs a no loss and no profit in the entire Transition.]

The common and frequently asked a question of Profit and Loss Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-3.4

Trick: If two article are sold at equal prices, the First one is sold at P% profit whereas the second one at a loss of L% then the

Profit And Loss Problem With Solution

Note: If +ve then profit or if -ve then loss

(Q1) A man sold two watches for Rs 525 each. On one he gains 10% and on the other he loses 15%. His profit or loss in the whole transaction is.

Solution:

Profit And Loss Problem With Solution

= ((100×-5)-2×10×15)/110+85

= (-500-300)/195

= -4.10% ie Loss= 4.10% Ans.

By Concept:

Profit And Loss Problem With Solution

100x ×(100+10)/100 = 525

⇒ (100x×110)/100 = 525

∴ x= 525/110

C.P of 1st watch= 100x

= 100×525/110

= Rs 477.27

Now,

Profit And Loss Problem With Solution

100x × (100-15)/100 = 525

⇒ (100x×85)/100 = 525

∴ x= 525/85 = 6.17

C.P of 2nd watch=100x

= 100×6.17

= Rs 617

Now,

Total C.P= Rs(477.27+617)

= Rs 1094.27=1094

Total S.P= 525+525 = Rs 1050

Loss= C.P – S.P

= Rs(1094 – 1050)

= Rs 48

% Loss= (48×100)1094

= 4.10% Ans.

Profit and Loss Problem with solution and Shortcut Tricks for Bank PO, SSC CGL, SSC CHSL, Railway Exam Type-2.In this type, I have already shared a Profit and Loss Problem with solution, Shortcut Tricks, Basic concept and frequently asked question if you have not read that yet, you should read it the right way here is the link.

Profit and Loss Problem Shortcut Tricks Type-2

If you have any queries regarding this topic fell free to ask me in the comments below.

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