Important percentage problem concepts and shortcut tricks type-1

Last updated on October 6th, 2019 at 06:25 pm

In quantitative aptitude Percentage chapter plays an important role in any competitive examination like SSC CGL,SSC CHSL, SBI PO, SBI Clerks, IBPS PO, IBPS Clerks,railways and Lic etc so i have explained basic to advanced percentage problem concepts,shortcut tricks and solution which will help you scoring good marks in exam and also save your valuable time.
In Quantitative Aptitude Percentage concept helps to solving a problem of Data Interpretation, Profit and loss, SI and CI, Mixture and allegations etc.In this post i have covered introduction and the very common type of percentage problem that are frequently asked in various competitive exam.

=> To express X% as a fraction

 X%=X/100

For example: 56%

56%=56/100=14/25

=> Suppose A=120

                        B=150

(Q1)->A is a what percent(%) of B ?

Solution: X%(let) of B=A

(X/100) ×150 =120

∴ X=(120×100)/150

=80% ans

(Q2)->B is what % of A ?

solution: X% of A=B

(X/100) ×120 =150

∴ X=(150×100)/120

=125% ans.

(Q3)->B is how % more than A ?

Solution: difference=150-120=30

∴ Required percentage = (30×100)/120

=25% ans.

(Q4)->A is how % less than B ?

Solution: difference=150-120=30

∴ Required percentage = (30×100)/150

=20% ans.

Percentage Problem Concept:

* Suppose X increases by 40% means

X×(100+40)/100

=(X×140)/100 

* Suppose X decreases by 30% means

X×(100-30)/100

=(X×70)/100

(Q1)->If salary of A is 300. now 40% increases then new salary of A.

Solution:

(Q2)->If salary of A is 300. now 40% decreases then new salary of A.

Solution:

(Q3)->Salary of A is 120.now what percent of salary increases then new salary of A is 144 ?

Solution:

   % increase=(24×100)/120

                         = 20% Ans

Note: Rs 24, Rs 120 पर increase हो रहा है तो percentage हमेशा initial amount पर calculate किया जाता है न कि increased वाले amount पर .

(Q4)->If salary of A increases 40% then new salary of A is 490.find out initial salary

Solution:

             Now

                     (X×140)/100=490

                     ∴ X=(490×100)/140

                            =350Ans

Common type of percentage problem that are frequently asked in various competitive exam

(Q1)->If x% of Y% of 80 is the same as 25% of 900 then the value of xy is.

Solution: 80×(y/100)×(x/100)=900×(25/100)

                 => 4xy/500=25×9

                  ∴xy=(25×9×500)/4

                         =28125 Ans

(Q2)->If 40% of 4/5 of 3/4 of a number is 48, then what is 1% of the same number?

Solution:Let the number be x

                => x×(3/4)×(4/5)×(40/100)=48

               ∴ x=(48×4×5×100)/(3×4×40)

                    =200

Now, 1% of 200=200×(1/100)

                            =2 Ans.

(Q3)->What percent of 15 hours is 18 seconds?

Solution:x% of 15 hours = 18 seconds

                => x% of 15×60×60 seconds =18 seconds

                => 15×60×60×(x/100)=18

                ∴ x=(18×100)/(15×60×60)

                     =1/30% Ans

(Q4)->What percent of 3.5 kg is 70 gms?

Solution:x% of 3.5 kg=70 gms

                => x%×3.5×1000 gms=70 gms

                => (x/100)×3.5×1000 gms=70gms

                ∴ x=(70×100)/3.5×1000

                      =2% Ans.

(Q5)->50% of a number when added to 50 is equal to the number. The number is.

Solution:Let the number be 100x

                => 100x×(50/100)+50=100x

                => 50x+50=100x

                => 50x=50

                ∴ x=1

Number=100x

                =100×1

                 =100 Ans

Also Read;

Percentage Questions Type-6

Percentage Questions Type-8

(Q6)->When 75 is added to 75% of a number,the answer is the number. Find 40% of that number.

Solution:Let the number be 100x

                 =>100x×75%+75=100x

                =>100x ×(75/100)+75=100x

                =>75x+75=100x

                ∴ x=3

Number=100x

               =100×3

               =300 

Now 40% of 300=(300×40)/100

                            =120 Ans.

(Q7)->The number that is to be added to 10% of 320 to have the sum as 30% of 230 is.

Solution:Let the number to be added=x

                =>320×(10/100)+x = (230×30)100

                =>32+x = 69

                ∴ x=37 Ans

(Q8)->If 60% of A=30% of B,B=40% of c,c=x% of A,then value of x is.

Solution:A×(60/100) = B×(30/100)

                =>3A/5 = 3B/10

                =>3A/5 = (3/10)×(2C/5)

                =>3A/5 = 6C/50

                =>3A/5 = (6/50)(Ax/100)

                ∴ x=(50×100×3A)/6A×5

                      =500 Ans

Rough:B=C×(40/100)

                 =2C/5

             C =A×(x/100)

                 =Ax/100

(Q9)->51% of a whole number is 714. 25% of that number is.

Solution:Let the whole number be 100x

                =>100x×51% = 714

                =>100x ×(51/100) = 714

                ∴ x=14

whole number=100x

                          =100×14

                          =1400 Ans.

Now, 25% of 1400=(25/100)×1400

                                 =350 Ans.

(Q10)->83¹/3% of Rs 90 is equal to 60% of ?

Solution:90×83¹/3%=x×60%

                =>90 ×(250 /3×100)=x ×(60/100)

                ∴ x=(250×90×100)/(3×100×60)

                     =125 Ans.

(Q11)->If 8% of x=4% of y,then 20% of x is.

Option:(a)10% of y (b)16%of y (c)40% of y (c)80% of y

Solution: x ×(8/100)=y ×(4/100)

                =>8x=4y

                ∴ x=y/2

let,

20% of x = z% of y

(20/100)× x = y ×(z/100)

20x=yz

20×y/2 =yz      [x=y/2]

∴ z=10% Ans.

(Q12)->If 30% of A is added to 40% of B,the answer is 80% of B.what percentage of A is B ?

Solution:A×(30/100)+B×(40/100)=B×(80/100)

                =>(3A/10)+(4B/10)=8B/10

                =>3A+4B=8B

                =>3A=4B

                ∴ A/B=4/3

Now, x% of A=B

          (x/100)×A=B

           xA=B×100

           x=100B/A

             =100×3/4

             =75% Ans.

Percentage Solution Type-2

Percentage Solution Type-3

Percentage Solution Type-9